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2 years ago

PLEASSE HEP MEEEEEEEE

Mathematics

1 answer:

DENIUS [597]2 years ago

3 0

Answer:

s = 70

Step-by-step explanation:

$\frac{s}{10} = 7$

$10 \times \frac{s}{10} = 10 \times 7$

$s = 70$

<h2>Insta: 25k_kem</h2>

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Find the value of 5 ∙ 23. <br><br> 30<br><br> 40 <br><br> 1,000<br><br> ASAP

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The value of 5 ∙ 23 is 115.

The small dot is typically used as a multiplication symbol. When we multiply these two numbers the result is 115.

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For the following graph, determine if the graph represents a polynomial function. If it is a polynomial function, then determine

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Using function concepts, it is found that the correct option is given by:

a.Yes, this graph represents a polynomial. There are two turning points and the least degree possible is three.

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Supposing a polynomial with n turning points, the least possible degree is of n + 1.

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1 year ago

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Answer:

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Step-by-step explanation:

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3 years ago

USA Today reports that about 25% of all prison parolees become repeat offenders. Alice is a social worker whose job is to counse

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Answer:

a) $P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

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b) $E(X) = np = 4*0.75=3$

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And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=1-0.25=0.75)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

Part b

The expected value is givn by:

$E(X) = np = 4*0.75=3$

Part c

For the standard deviation we have this:

$Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

$P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

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Ipatiy [6.2K]

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