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3 years ago

What is the value of X???

Mathematics

1 answer:

nexus9112 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

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X^2=81/100 solve the equation for x

grigory [225]

DAD?????????????????????

5 0

3 years ago

What is this in simplest form?

Norma-Jean [14]

Answer:

1/4

Step-by-step explanation

you divide 25 divided by 25 the also divide 100 divided by 25 and u get 1/4

7 0

4 years ago

Read 2 more answers

The volume of a shipping container is 448.656 cubic inches, and it can hold 24 smaller boxes. What's the volume of each of the s

madreJ [45]

Answer:

The volume of each of the smaller boxes = 18.694 inches³

Step-by-step explanation:

The volume of Shipping container = 448.656 inches³

The shipping container hold small boxes of numbers = 24

So, The volume of each of small boxes = $\frac{448.656}{24}$ inches³

Or, The volume of each of small boxes = 18.694 inches³

Hence The volume of each of 24 small containers is 18.694 inches³ Answer

5 0

4 years ago

Graph the inequality in the coordinate plane:<br><br> x<-3

tensa zangetsu [6.8K]

Answer:

Graph of the inequality x< -3 as shown below in the figure.

Step-by-step explanation:

Given the inequality: x < -3

Graph of this inequality as shown below in the figure.

All the points that are lie in the shaded area satisfy the equation x < -3 or

In other words, we can say that x can take any value less than -3 .

x ≠ -3 or any number that is greater than -3.

Since there is a strict inequality i.e x < -3 , the points that lie on the line x = -3 does not satisfy the equation.

Therefore, the dotted line is marked at x = -3

8 0

3 years ago

Find the area of the surface. the part of the hyperbolic paraboloid z = y2 − x2 that lies between the cylinders x2 + y2 = 16 and

meriva

Parameterize the surface (call it $\mathcal S$ ) by

$\mathbf s(u,v)=\langle u\cos v,u\sin v,u^2\sin^2v-u^2\cos^2v\rangle=\langle u\cos v,u\sin v,-u^2\cos2v\rangle$

with $4\le u\le5$ and $0\le v\le2\pi$ , which yields

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

Then the area of $\mathcal S$ is given by the surface integral

$\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=4}^{u=5}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv=\dfrac{(101^{3/2}-65^{3/2})\pi}6$

8 0

3 years ago