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musickatia [10]
3 years ago
10

-1/4 [p+16]=2 help me pls

Mathematics
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

6p

Step-by-step explanation:

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4x-1/2=x+7<br> Ah I need help I’m really not sure
guajiro [1.7K]

4x - 1/2 = x + 7

4x - x - 1/2 = 7

3x - 1/2 = 7

3x = 7 + 1/2

3x = 7.5

x = 7.5 ÷ 3

x = 2.5

7 0
3 years ago
What are the measures of line segments AB and AC?
Doss [256]

Answer:

So you want to know the number of a b and c?

Step-by-step explanation :

7 0
3 years ago
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A rope is cut into three pieces P, Q, and R the lengths of the pieces are in the ratio 3:5:7 if the rope is 33 feet 9 inches, fi
Olin [163]
P-81
q-135
r-189
find out how many inches the rope is then divide by 15 total parts then multiply each ratio by that
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3 years ago
Negitive 7 over 18 minus negitive 9 over 4 equals?​
Inessa [10]

Answer:

1 31/36 is your answer

Step-by-step explanation:

Find common denominators. Note that what you do to the denominator, you must do to the numerator;

(-7/18)(2/2) = (-14/36)

(-9/4)(9/9) = (-81/36)

Combine the terms:

(-14/36) - (-81/36)

Note that two negative signs directly next to each other equals a positive sign.

(-14/36) + 81/36

-14/36 + 81/36

(-14 + 81)/36

Combine like terms. Solve the parenthesis:

(67)/36

Change to a mixed fraction:

(67/36) = 1 31/36

1 31/36 is your answer.

~

5 0
3 years ago
A 16-inch candle is lit and burns at a constant rate of 0.8 inches per hour. Let t represent the number of hours since the candl
Tamiku [17]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

a.

The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.

After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.

After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.

Hence, the length of the candle after t hours when it was lit can be represented by the function, f(t) = 16 - 0.8t. f(t) = 0 at t = 20.

b.

The domain of the function is 0 to 20.

c.

The range is 0 to 16.

8 0
4 years ago
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