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Dmitry [639]
3 years ago
6

Help please thanks!! (:

Mathematics
1 answer:
Masja [62]3 years ago
5 0
The first thing we do in a problem like this is let arc AB equal X. X is the magic letter, anything you need to find name it x. We also know that all arcs in a circle must add up to 360, so arc ALB is equal to 360 - x.

There's this theorem saying that when two tangents intersect from a point outside a triangle, the measure of the angle formed by the intersection of the tangents (angle P) is equal to the half the difference of the arcs. 
This basically means:

angle P = 1/2(360 - x) - x.
plug in the value of angle P
84 = 1/2(360 - x - x)
168=360 - 2x
2x = 192
x = 96

arc AB=96
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Firlakuza [10]
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3 years ago
Elimination_4x_2y=14<br> _10x+7y=_24
Gnesinka [82]

Answer:

The answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

-4x-2y=14   ......(1)

-10x+7y=-24 ......(2)

So, we multiply the equation (1) by 7 we get:

-28x-14y=98

And, we multiply the equation (2) by 2 we get:

-20x+14y=-48

Now, adding both the new equations:

-28x-14y+(-20x+14y)=98+(-48)

-28x-14y-20x+14y=98-48

-28x-20x-14y+14y=50

-8x=50

<em>Dividing both the sides by -8 we get:</em>

x=-\frac{50}{8}

Now, putting the value of x in equation (1):

-4x-2y=14

-4(-\frac{50}{8})-2y=14

\frac{200}{8} -2y=14

25-2y=14

<em>Subtracting both sides by 25 we get:</em>

-2y=-11

<em>Dividing both sides by -2 we get:</em>

y=\frac{11}{2}

Therefore, the answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

5 0
3 years ago
Find the highest common factor of 35 and 8C.
Kaylis [27]

Answer:

Factors of 35 = 1, 5, 7 and 35

Factors of 8= 1, 2, 4, 8.

common = 1

7 0
3 years ago
A population of 360 field mice live inside of a small area of forest near your house.240 of the mice are brown, and 120 of the m
OlgaM077 [116]
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The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th
USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

  • H_{0}: μ=523
  • H_{a}: μ>523

The conclusion is failure to reject the null hypothesis.

This means that <em>test statistic</em> is lower than <em>critical value</em>.  Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0
3 years ago
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