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Evgesh-ka [11]
3 years ago
7

A plant can be classified in more than one category. True False

Biology
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

true

Explanation:

theres a bunch of different categories depending on the subject

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Which sequence of RNA transcribed from the base sequence of DNA is ATA CCG ATC GAT
HACTEHA [7]

Answer:

a

Explanation:

this image shows what each letter changes to.

6 0
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In what type of circulation does the oxygenated blood flow between the heart and the cells of the body
arlik [135]
Systematic circulation
6 0
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Law vs theory compare and contrast please really need help !!!
Sergeu [11.5K]
Some are:
-laws tell how
- laws are proven true
- Theories attempt to explain
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- hypothesis is an educated guess
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8 0
3 years ago
The simple interest on a loans of $200 at 10 percent interest per year is
inysia [295]
<h2>Simple Interest on a Loans - Option C</h2>

The simple interest on loans of $200 at 10 percent interest per year is $20 per year until the loan is paid off. Interest per year means the expense of interest that is charged for annum as a percentage of the value which is hired.

In order to calculate interest per year, multiply the principal basis for the rent by the interest per year then divide the value of interest per year by 12 (number of months in a year). Therefore, for simple interest on loans of 200 dollars at 10 percent interest per year, we calculate 20 dollars per year until the loan is paid off.


6 0
3 years ago
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A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
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