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NikAS [45]
3 years ago
6

  WHO KNOWS FUNCTIONS AND ALL THAT PLZZZ HELP ME ASAP I REALLY NEED IT PLZZ

Mathematics
1 answer:
S_A_V [24]3 years ago
8 0

Answer:

No, because two different 6 is paired with two different y-values

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I am stuck on how to do 10 percent of $55.86
faust18 [17]

Answer:

read step by step

Step-by-step explanation:

.10×55.86 = 5.58

then subtract $5.58 from your total .

and that will give you the answer

8 0
3 years ago
I need help with q5
Roman55 [17]
Percent increase = ((new number - original number) / (original number)) x 100.

percent increase = ((3000 - 2500) / 2500)) x 100 =
                                   (500 / 2500)....x 100 =
                                     0.2 x 100 =
                                      20% increase <====
                                
7 0
3 years ago
Find the measure of the angle indicated in bold
vova2212 [387]

Answer:

60 for both

Step-by-step explanation:

Since these angles are parallel, they are equal to each other :

6x = 5x + 10

Subtracting 5x from both sides gives us :

x = 10

Substituting this value back into both angles gives us

6x = 60

5x+10 = 60

8 0
2 years ago
Put in order from least to greatest<br> 2/3 0.6 - 5/6 - 6.6
valentina_108 [34]
-6.6.-5/6.0.6,2/3"""""""""""""""""
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4 0
2 years ago
What is a31 of the<br> arithmetic sequence for<br> which a5 = 12.4 and<br> ag = : 22.4?
MrMuchimi

The value of a₃₁ of the arithmetic sequence exists 77.4.

<h3>How to find the value of a₃₁ of the arithmetic sequence?</h3>

Given: a₅ = 12.4 and a₉ = : 22.4

For the arithmetic sequence a₁, a₂, a₃, ..., the n-th term exists

where d = common difference

a₅ = 12.4,

a₁ + 4d = 12.4 .........(1)

Because a₉ = 22.4,

a₁ + 8d = 22.4 .........(2)

Subtract (1) from (2), we get

a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4

4d = 10

Dividing throughout by 4, we get

d = 2.5

From (1), we get

a₁ = 12.4 - 4 * 2.5 = 2.4

a₃₁ = 2.4 + 30 * 2.5 = 77.4

Therefore, the correct answer is a₃₁ = 77.4

To learn more about the arithmetic sequence refer to; brainly.com/question/6561461

#SPJ9

8 0
1 year ago
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