area: 18 units^2
Step-by-step explanation:
the shape is a quadrilateral, with one slanted side, so I separated the shape into a rectangle and triangle, and and calculated their area respectively, then added the products up. please correct me if I'm wrong. hope this helped. :)
Answer:
The answer is (x - 9)(x - 2), or x2 - 11 + 18.
Step-by-step explanation:
Well, think about it. What two numbers add to -11 and multiply to get 18? -9 and -2 add to get -11 and multiply to get 18.
4) (log3)14/(log3)4
hope dis helps<span />
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
