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3 years ago

7. Which of the following could form a unique triangle? Select all that apply.

Mathematics

1 answer:

baherus [9]3 years ago

7 0

Answer:

If you are given two lengths and an angle between them (called the included angle) can you produce a unique triangle? In this interactive, you will be given different sets of two sides with the included angle. For each set, see if more than one triangle can be produced.

Step-by-step explanation:

You used side-angle-side, or SAS, to construct the triangles in the interactive. It is important to note that SAS construction will always produce one, unique triangle. It does not matter how much you flip, rotate or move the triangle, the measurements will not change. Even though the triangle may "look" different, it still has the same angle measures and side lengths. The orientation of a shape will never change the dimensions, just the placement.

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Find the 10th partial sum of the arithmetic sequence defined by

Evgesh-ka [11]

Answer:

22.5

Step-by-step explanation:

If you expand the series, you can see the first few terms of the series:

Putting 1 in $n$ , $\frac{1}{2}(1)-\frac{1}{2}=0$
Putting 2 in $n$ , $\frac{1}{2}(2)-\frac{1}{2}=0.5$
Putting 3 in $n$ , $\frac{1}{2}(3)-\frac{1}{2}=1$
Putting 4 in $n$ , $\frac{1}{2}(4)-\frac{1}{2}=1.5$

We can see the series is 0, 0.5, 1, 1.5, ....

This is an arithmetic series with common difference (the difference in 2 terms) 0.5 and first term 0.

We know formula for sum of arithmetic series:

$s_{n}=\frac{n}{2}(2a+(n-1)d)$

Where,

$S_{n}$ denotes the nth partial sum
$a$ is the first term (in our case it is 0)
$n$ is the term (in our case it is 10 since we want to find 10th partial sum -- sum until first 10 terms)
$d$ is the common difference (difference in term and the previous term) (in our case it is 0.5)

Substituting these into the formula, we get the 10th partial sum to be:

$s_{10}=\frac{10}{2}(2(0)+(10-1)(0.5))\\s_{10}=5(0+(9)(0.5))\\s_{10}=5(0+4.5)\\s_{10}=5(4.5)\\s_{10}=22.5$

So the sum of the first 10 terms is 22.5. Third answer choice is right.

8 0

3 years ago

Read 2 more answers

Which of the following can be used to find the sum of the interior angles for

Yanka [14]

D. Subtract 2 from the number of sides and multiply the difference by 180

6 0

2 years ago

What is the solution of the system of equations? -y+3x=6 y=-6x+12

irinina [24]

Answer:

x = 2

y = 0

Step-by-step explanation:

We can solve using substitution, substitute y in the first equation with the second equation:

-(-6x + 12) + 3x = 6

Distribute the negative sign:

6x - 12 + 3x = 6

Combine like terms:

9x - 12 = 6

Isolate the variable and solve for x by adding 12 in both sides:

9x = 18

x = 2

Substitute 2 with x in any equation to find the value of y:

-y + 3(2) = 6

-y + 6 = 6

Subtract 6 in both sides to isolate the variable:

-y = 0

0/-1 = 0

y = 0

Our answer would be x = 2 and y = 0

8 0

3 years ago

Read 2 more answers

I will give you a Brainly crown if it is right. Will you help me

Lostsunrise [7]

Answer:

-12

Step-by-step explanation:

4 time 3 is 12

since he owes her its negative, so it is -12

3 0

3 years ago

Read 2 more answers

What is the ratio of x to y?

abruzzese [7]

$\frac{3}{2} = \frac{2x}{2x+y}$

From any proportion, we get another proportion by inverting the extremes (or the means):

$\frac{2x+y}{2} = \frac{2x}{3}$ = k

so we have:

2x=3k
2x+y=2k therefore:
3k+y=2k
y= - k

x= $\frac{3}{2} k$

$\frac{x}{y}$ = - $\frac{3}{2}$

The corect answer is A. -3/2

or:

$\frac{3}{2} = \frac{2x}{2x+y}$

From any proportion, we get another proportion by inverting the extremes and the means:

$\frac{2x+y}{2x} = \frac{2}{3}$

We use a property of proportions:

$\frac{a}{b} = \frac{c}{d}$ where a, d are extremes and b,c are means and the product of the extremes equals the product of the means (a*d=b*c),

so we have

$\frac{a-b}{b} = \frac{c-d}{d}$ or

$\frac{a+b}{b} = \frac{c+d}{d}$ (you can check this also by "the product of the extremes equals the product of the means")

$\frac{2x+y}{2x} = \frac{2}{3}$

$\frac{(2x+y)-2x}{2x} = \frac{2-3}{3}$

$\frac{y}{2x} = \frac{-1}{3}$

3y = - 2x

$\frac{x}{y} = -\frac{3}{2}$

4 0

3 years ago