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3 years ago

14

A quantity with an initial value of 220 grows continuously at a rate of 9.5% per hour. What is the value of the quantity after 2

55 minutes, to the nearest hundredth?

1 answer:

Mazyrski [523]3 years ago

6 0

Answer:

i need help

Step-by-step explanation:

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What is the height of a cylinder with a volume of 1205.76 cubic inches and a radius of 8 inches? Round to the nearest tenth of a

Anit [1.1K]

Cylinder height = volume / PI * radius^2
cylinder height =1,205.76 / PI * 8^2
cylinder height = <span> <span> <span> 5.9969582557 </span> </span> </span>
which I guess can be safely rounded to 6 inches
Source www.1728.com.diamform.htm

3 0

3 years ago

Can anyone help me with this? Thanks!

Katarina [22]

Answer:

Step-by-step explanation:

5^2+8^2=c^2

25+64=89

89=c^2

square root of 89 is 9.43

9.43=the square root of c^2

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3 years ago

Write the equation of the given line in standard form.

ollegr [7]

let's notice that the x-coordinate is the same for both points.

Check the picture below.

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4 years ago

Solve 7^x=12 <br> round to the nearest ten-thousandth

Anton [14]

Answer:

x=1.277

Step-by-step explanation:

Not Available.

4 0

3 years ago

Find the amount to which $2,500 will grow if interest of 6.75% is compounded quarterly for 10

andreev551 [17]

Answer:

Part a

For this case n = 4. If we use the future value formula we got:

$A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506$

Part b

For this case n = 365. If we use the future value formula we got:

$A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776$

Step-by-step explanation:

We can use the future vaue formula for compound interest given by:

$A= P(1+ \frac{r}{n})^{nt}$

Where P represent the present value, r=0.0675 , n is the number of times that the interest is compounded in a year and t the number of years.

Part a

For this case n = 4. If we use the future value formula we got:

$A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506$

Part b

For this case n = 365. If we use the future value formula we got:

$A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776$

5 0

3 years ago