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2 years ago

Help ASAP will give brainlist

Mathematics

1 answer:

sleet_krkn [62]2 years ago

5 0

Answer:

0.57142857

Step-by-step explanation:

i dont know why they said no decimal but i got 0.57142857

because

If you insist on converting 4/7 to a whole number, the best we can do is round the decimal number up or down to the nearest whole number. 4/7 rounded up to the nearest whole number is 1 and 4/7 rounded down to the nearest whole number is 0.

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Will give brainliest plz show work ASAP

MrMuchimi

Here is the work hope this helps!

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3 years ago

melomori [17]

You multiply straight across, and one number is a fraction and the other is not.

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3 years ago

How do you solve this problem.

Nat2105 [25]

Answer:

8 were yoused because 8 times 3 =24 so if you subtract you get 8

Step-by-step explanation:

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3 years ago

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The amount of green jelly beans in a bag is 25%. If there are 12 green jelly beans, how many total

maw [93]

Answer:

Step-by-step explanation:

25% is 1/4 of the bag. 12x4 = 48.

There are 48 jelly beans in the bag.

Hope that helps

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3 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago