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elena55 [62]
2 years ago
13

I REALLY NEED HELP PLEASE

Mathematics
1 answer:
vaieri [72.5K]2 years ago
8 0

Answer:

sin X =  12/13

cos X = 5/13

tan X = 12/5

Step-by-step explanation:

Recall the definitions as follows:

For a right triangle (i.e one angle is 90 deg) with one of the angles X

sin X = opposite side / hypotenuse

cos X = adjacent side / hypotenuse

tan X = opposite side / adjacent side

In our case for angle A, the following applies:

opposite = 36

adjacent = 15

hypotenuse = 39

hence

sin X = opposite side / hypotenuse = 36/39 = 12/13

cos X = adjacent side / hypotenuse = 15/39 = 5/13

tan X = opposite side / adjacent side = 36 /15 = 12/5

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Since a and 5 aren't like terms, you would write the expression as \frac{a+5}{b}

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For which fraction pairs would it be useful to use the benchmarks 0, One-half, and 1 to compare? Check all that apply.
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Answer:

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Step-by-step explanation:

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How to graph 3 points <br> f (x) = -2x + 5
Kisachek [45]
The first one is 0,5 the second one is 1,3 last one is 2,1 
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Describe how to determine which side of the boundary line should be shaded
iogann1982 [59]
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8 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

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So it has only 1 real number solution.

3. a=4, b=-3, c=-1

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So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
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