The circle goes thru the given points <span>(3,-4) And (3,5). Since the x-coordinate does not change, the diameter lies right on the vertical line x=3. Since the vertical distance between these points is 5-(-4), or 9, the radius is 9/2.
The standard eq'n of a circle is (x-h)^2 + (y-k)^2 = r^2
Let's subst. what we know: we get (x-3)^2 + (y-1/2)^2 = (9/2)^2. Note that y = 1/2 is halfway between y=-4 and y=5.</span>
First understand that this is a linear graph. Find 2 points on the graph. We can use (0,1) and (3,-3).
Look at how much the x increases, in this case the x value increases by 0+3, so 3.
Then see how much the y value increases (make sure to evaluate them in the same order) 1 + (-3) = -2.
So you know that the y value decreases by 2 units for every 3 unit increase in x. Therefore the slope is y=(-2/3)x
Then figure out what you add to the end. The y intercept is (0,1), so add 1 to the end of y=(-2/3)x to move it up.
Your resulting eq is y=(-2/3)x+1
Answer:
C
Step-by-step explanation:
2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm
