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marissa [1.9K]
3 years ago
14

Challenge A warehouse store sells 5.5-ounce cans of tuna in packages of 8. A package of 8 cans

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer:

Step-by-step explanation:

the warehouse is the best buy because you get 44oz off tuna but if you buy the three pack you get 19.5oz and if you buy the five pack from store you 22.5oz of tuna

so the warehouse has the best deal on tuna

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the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i
otez555 [7]
Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a
6 0
3 years ago
Write all the numbers that will round to 330
grandymaker [24]

Answer:

229.6 229.7 229.8 229.9 330.1 330.2 330.3 330.4

Step-by-step explanation:

idk

8 0
3 years ago
Pharoah Company had the following adjusted trial balance.
Scrat [10]

Answer:

The solution is given below

Step-by-step explanation:

The preparation of the post closing trial balance is given below

<u>Particulars                 Debit amount         Credit amount</u>

Cash                          $3,820

Account receivable  $4,040

Supplies                    $490

Account payable                                         $1,800

Unearned service revenue                         $180

Owner capital ($4,180 + $5,990 - $1,500 - $390 - $1,700 - $770) $5,810

Salary and wages payable                         $560

Total                    $8,350                            $8,350

4 0
2 years ago
I will give brainliest!
Makovka662 [10]
I would think the answer is 3, sorry if i cant help. 
3 0
3 years ago
Check answer please
Cerrena [4.2K]
The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}

\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}

Hope it helps.
5 0
3 years ago
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