$The\ volume\ of\ the\ cone:V=\dfrac{1}{3}\pi r^2H\\\\H=5\ in\\2r=4\ in\to r=2\ in\\\\subtitute\\\\V=\dfrac{1}{3}\pi\cdot2^2\cdot5=\dfrac{1}{3}\pi\cdot4\cdot5=\dfrac{20}{3}\pi\ (in^3)\\\\Answer:\boxed{V=\dfrac{20}{3}\pi\ in^3}$

7 0

3 years ago

Read 2 more answers

Solve the absolute value equation algebraically: 3|2x - 3| + 2 = 3

kupik [55]

Answer:

$3 |2x - 3| = 1$

$3 |2x - 3| = 1 \\ 6x - 9 = 1 \\ 6x = 10 \\ x = \frac{10}{6} = \frac{5}{3}$

$3 |2x - 3| = - 1 \\ 6x - 9 = - 1 \\ 6x = 8 \\ x = \frac{4}{3}$

$x = \frac{5}{3} x = \frac{4}{3}$

I am sorry but I am not sure of this :(

7 0

3 years ago

Graph F Distance from Home Time Is this graph functional?

KengaRu [80]

Answer:

what graph????

6 0

2 years ago

Quadrilateral missing angles

alukav5142 [94]

Answer:

idk

Step-by-step explanation:

sorry i needed the points sorry

3 0

3 years ago