Answer:
44
Step-by-step explanation:
Answer:
19 B is your answer thank you for.your question
bearing in mind that there are 90 feet between each base in a baseball diamond, so the total perimeter of it will be 90*4 = 360, one third of that is 360/3 = 120.
So Jones went 120 feet first and then another and so on, check the picture below.
using those values, can get the length of those sides, using the pythagorean theorem.
![\bf AH=\sqrt{HF^2+FA^2}\implies AH=\sqrt{9000} \\\\\\ AB=\sqrt{AS^2+SB^2}\implies AB=\sqrt{7200} \\\\\\ HB = AH = \sqrt{9000} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{\sqrt{9000}+\sqrt{7200}+\sqrt{7200}}\qquad \approx \qquad \stackrel{perimeter}{264.57}](https://tex.z-dn.net/?f=%5Cbf%20AH%3D%5Csqrt%7BHF%5E2%2BFA%5E2%7D%5Cimplies%20AH%3D%5Csqrt%7B9000%7D%20%5C%5C%5C%5C%5C%5C%20AB%3D%5Csqrt%7BAS%5E2%2BSB%5E2%7D%5Cimplies%20AB%3D%5Csqrt%7B7200%7D%20%5C%5C%5C%5C%5C%5C%20HB%20%3D%20AH%20%3D%20%5Csqrt%7B9000%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bperimeter%7D%7B%5Csqrt%7B9000%7D%2B%5Csqrt%7B7200%7D%2B%5Csqrt%7B7200%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%20%5Cstackrel%7Bperimeter%7D%7B264.57%7D)
now, we can plug those values in the Heron's Area Formula to get its area.
![\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{9000}\\ b=\sqrt{7200}\\ c=\sqrt{7200}\\ s\approx 132.29 \end{cases} \\\\\\ A=\sqrt{132.29(132.29-\sqrt{9000})(132.29-\sqrt{7200})(132.29-\sqrt{7200})} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A\approx 3337.289~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BHeron%27s%20area%20formula%7D%20%5C%5C%5C%5C%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D%5Csqrt%7B9000%7D%5C%5C%20b%3D%5Csqrt%7B7200%7D%5C%5C%20c%3D%5Csqrt%7B7200%7D%5C%5C%20s%5Capprox%20132.29%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B132.29%28132.29-%5Csqrt%7B9000%7D%29%28132.29-%5Csqrt%7B7200%7D%29%28132.29-%5Csqrt%7B7200%7D%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20A%5Capprox%203337.289~%5Chfill)
Answer:
The length would be 31.5ft and the width would be 26.5ft
Step-by-step explanation:
For the purpose of this, we'll set the width as x. We can then define the length as x + 5 since we know it is 5 ft longer than the width. Now we can use those along with the perimeter formula to solve for the width.
P = 2l + 2w
116 = 2(x + 5) + 2(x)
116 = 2x + 10 + 2x
116 = 4x + 10
106 = 4x
26.5 = x
Now since we know that the width is 26.5ft, we can add 5ft to it to get the length, which would be 31.5ft.
Well assuming that the Pool doesn't have a limit on the amount of gallons of water it can hold
5858* 3434 = 20116372
