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3 years ago

Howdo you mutiply mixed numbers?

Mathematics

1 answer:

yawa3891 [41]3 years ago

5 0

Answer:

Make each number on the fraction an improper fraction

Then simplify it

Then multiply the numerator and denominator

put the answer in a short term

And make sure the answer makes sense

Guess what?

I am also learning about multiplying mixed numbers too!

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40 points to whoever can answer for me!

luda_lava [24]

Answer:

x≤-3 2 ≤x<7

Step-by-step explanation:

(x^2+x-6) /(x-7) ≤0

Factor the numerator

(x+3)(x-2) / (x-7)≤0

Critical points are

X =-3 X =2 X=7

We need to check the values when

x≤3 -3 ≤ x≤2 2 ≤x<7 x>7

(x cannot be 7 because then the denominator is zero)

and see when it is less than 0

Substitute a value in and see if factor is positive or negative

x≤-3

(negative)(negative) / (negative) = negative

-3 ≤x≤2

(positive)(negative) / (negative) = positive this range does not work

2 ≤x<7

(positive)(positive) / (negative) = negative

x>7

(positive)(positive) / (positive)

8 0

3 years ago

Read 2 more answers

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

How much do I shade in

lara [203]

4/10 is equal to 4 out of 10 or 40%
This means you should shade 4 of the 10 blocks

3 0

3 years ago

Read 2 more answers

Help is it positive 22 and negetive 27 or or 6 and postive 1

anygoal [31]

Is that edgenuity??

4 0

3 years ago

67 1/2 * (-1/3) it is due on Wednesday and for some reason I cont figure out this one

krok68 [10]

Answer:

-45/2

Step-by-step explanation:

67 1/2 * (-1/3)

67 1/2 = 135/2

So 135/2*1/3=45/2

45/2*-1=-45/2

7 0

1 year ago