Answer:
except
you can use github copilot for this question
Thank you for being the rare question where you actually provide what language you want your answer in; I approve, and encourage this.
In Java, the following will work.
I made it a bit more versatile to work with others numbers, other than 99, if you so please (if not, just hardcode the 99 in yourself).
// Example list - fill this with numbers yourself.
ArrayList<Integer> nums = new ArrayList<>();
int n = 99;
int count = (int)nums.stream().filter(i -> i == n).count();
System.out.println(n + " occurences.");
Answer:
The answer is 500 kbps
Explanation:
Consider the given data in the question.
R1 = 500 kbps
R2=2 Mbps
R3 = 1 Mbps
Now as it is mentioned that there is no other traffic in the network.
Thus,
throughput of the file = min {R1,R2,R3}
throughput of the file = min {500 kbps, 2 Mbps, 1 Mbps}
T/P of the file = 500 kbps
Answer:
DDR3 SDRAM having twice rate of data transferring as compared to DDR2 SDRAM both have 240 pin connection. DDR3 memory power consumption is 40 % less as compared to DDR2. both are transfers data on a 64 data bits wide bus. The physical difference occur in both type a cut is present at bottom along pin in DDR2 it is occur probably in center and In DDR3 it is occur at left through center.
