Answer:
The technician should delete the startup configuration and the "vlan.dat" file residing in the flash memory of the newly added switch and lastly, he should reboot the switch.
Explanation:
In this scenario, a Cisco Catalyst switch has been added to support the use of multiple virtual local area networks (VLANs) as part of an enterprise network. The network technician finds it necessary to clear all virtual local area network (VLAN) information from the switch in order to incorporate a new network design. To accomplish this task successfully, the technician should delete the startup configuration and the "vlan.dat" file residing in the flash memory of the newly added switch and lastly, he should reboot the switch. The VLAN informations are stored in a file with the name "vlan.dat" residing in the flash memory of the switch.
However, in order to delete the startup configuration he would be required to login as an administrator, so as to have all privileges.
<em>Also, the essence of deleting the startup configuration and the "vlan.dat" is to avoid any conflict in the network. </em>
Answer:
number1 = int(input("Enter the first number: "))
number2 = int(input("Enter the second number: "))
result = 0
for i in range(number1):
result += number2
print(str(result))
Explanation:
Ask the user for two numbers
Initialize result as 0 to hold the multiplication of the numbers
Create a for loop that iterates "number1" times. In each iteration, add number2 to the result.
When the loop is done, print the result
Answer:
Data type in Microsoft Access Database
Text
Memo
Byte
Integer
Long
Single
Double
Currency
AutoNumber
Date/Time
Yes/No
Ole Object
Hyperlink
Lookup Wizard
Explanation:
Answer:
115200000 bits
Explanation:
Given Data:
Total Time = 3 minute = 3 x 60 sec = 180 sec
Sampling rate = 40,000 bits / sample
Each sample contain bits = 16 bits /sample
Total bits of song = ?
Solution
Total bits of song = Total Time x Sampling rate x Each sample contain bits
= 180 sec x 40,000 bits / sec x 16 bits /sample
= 115200000 bits
= 115200000/8 bits
= 14400000 bytes
= 144 MB
There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.
Answer:
hi earlier u told me to answer ur question but i couldn't respond in the comments cos it said something went wrong
Explanation:
do i answer this question seriously or is this answer good?? srry im kinda dûmb T-T
