Ask question

Ask question

All categories

3 years ago

12

find the number of terms in an AP given that it's first and last terms are a & 37a respectively and it's common difference i

s 4a

1 answer:

KiRa [710]3 years ago

6 0

Answer:

Substitute the values give into the nth term of the arithmetic progression and solve this the steps are give above in the picture

You might be interested in

What is 4 multiplied by 4/6

yawa3891 [41]

Okay,

1. Multiply 4 x 4.

2. Then Since 4 x 4 is 16 it would be 16 over 6 ( $\frac{16}{6}$ )

3. Then Simplify, 6 can go into 16 twice, being 12.

4. There is 4 left over, so put 4 over 6 ( $\frac{4}{6}$ )

5. Finally, simplify again, 4 can be divided by 2, so can 6, make it 2 over 3 ( $\frac{2}{3}$ )

Answer: 12 and 2 over 3 ( $12 \frac{2}{3}$ )

**Hope I Helped!**

5 0

4 years ago

Read 2 more answers

To the Pythagorean Theorem

Aloiza [94]

Answer:

x = 29

Step-by-step explanation:

$c^{2} = a^{2} + b^{2}$

$c^{2} = 20^{2} + 21^{2}$

$c^{2} = 400 + 441$

$c^{2} = 841$

$\sqrt{c^2} = \sqrt{841}$

$c = 29$

4 0

3 years ago

3^2 • 3^-8 • 3^0<br> i need help with this asap

pantera1 [17]

Steps to solve:

3^2 • 3^-8 • 3^0

~Apple exponent rule [ a^b * a^c = a^b+c ]

3^2-8+0

~Simplify

3^-6

~Use exponent rule [ a^-b = 1/a^b ]

1/3^6

~Simplify

1/729

Best of Luck!

6 0

3 years ago

Read 2 more answers

The polygons are regular polygons. What is the area of the shaded region to the nearest tenth? (see attachment)

Fynjy0 [20]

Area of shaded region = 2(4*4)=2*16=32 in squared

hope helped

8 0

3 years ago

Read 2 more answers

Can someone solve this

Natalka [10]

Option D:

ΔCAN ≅ ΔWNA by SAS congruence rule.

Solution:

Given data:

m∠CNA = m∠WAN and CN = WA

To prove that ΔCAN ≅ ΔWNA:

In ΔCAN and ΔWNA,

CN = WA (given side)

∠CNA = ∠WAN (given angle)

NA = NA (reflexive side)

Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.

Hence option D is the correct answer.

4 0

3 years ago