Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Composite function</u>
<u>The denominator can't be zero</u>
If x = -2, y = 6.
To solve this quesiton, we need to find the value of y if x is equal to -2. We can do this by substiuting the value of x and then solving.
y = 2 (-2) + 10
y = -4 + 10
y = 6
The correct answer for the question that is being presented above is this one: "0.5" <span>The probability that a normal random variable is less than its mean is 0.5. In a normal distribution, 1.0 refers to the one that is stable and is in equilibrium.</span>
Pretty sure the answer is $600
Hope this helps
