1small bus=12
large bus=24
total passengers is 780
total busses is 20
# of small bus =x
# of large bus=y
so x+y=20
every one x=12 people so
780=12x+24y
the 2 equations are
x+y=20
12x+24y=780
Store sells wheels in pachages of 2 and 3
40 packs and 100 wheels
1 pack of 2 =2 so
# of 2 pack=x
# of 3 pack=y
x+y=40
2x+3y=100
those are the 2 equations
So to begin, substitute all of the variables in for their corresponding value.
X=3
Y=-5
Z=-1
2XY+6YZ^2
2(3)(-5)+6(-5)(-1^2)
-30+-30
-60
Hopefully this is what they're asking for!
Answer:
a. 28.
b 20.78.
Step-by-step explanation:
a. f(x) = 0.001(x - 10)(x + 20)(x - 40)
When x = 50
Height = f(40) = 0.001(50-10)(50+20)(50-40)
= 0.001(40*70*10)
= 0.001 * 28,000
= 28 units.
b.
Expanding the function we get
f(x) = 0.001(x - 10)(x^2 - 20x - 800)
f(x) = 0.001(x^3 - 30x^2 - 600x + 8000)
f(x) = 0.001x^3 - 0.03x^2 - 0.6x + 8
Finding the derivative
f'(x) = 0.003x^2 - 0.06x - 0.6
This is zero for maxm/minm values:
0.003x^2 - 0.06x - 0.6 = 0
x = 27.32, - 7.32.
The values of the heights corresponding to these values of x are:
0.001(27.32-10)(27.32+20)(27.32-40)
= -10.39. and
0.001(-7.32-10)(-7.32+20)(-7.32-40)
= 10.39.
So the distance between A and B = 10.39 - (-10.39)
= 20.78.
Answer:
70th percentile for the amount of time between customers entering is 30.10
Step-by-step explanation:
given data
mean = 25
to find out
What is the 70th percentile for the amount of time between customers entering Clay's store
solution
we know that here mean is
mean = ..................1
so here 25 =
and we consider time value corresponding to 70th percentile = x
so we can say
P(X < x) = 1 -
P(X < x) = 70 %
1 - = 70 %
1 - = 0.70
= 0.30
take ln both side
= ln 0.30
= 1.203973
x = 30.10
70th percentile for the amount of time between customers entering is 30.10
1/3
I was taught to divide each side by the same number
8/8= 1
24/8=3
=1/3