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Semmy [17]
2 years ago
9

Which of the following ratios is equivalent to the ratio 3:4?

Mathematics
2 answers:
pentagon [3]2 years ago
7 0
Well if you have to make one up, something like 6:8 would be equivalent because you multiply both by 2. but if not, why are the answer choices?
natta225 [31]2 years ago
6 0
What’re the choices you have
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andriy [413]
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4 0
3 years ago
The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope
NARA [144]

Answer:

a) (i) m = 2.22, (ii) m = 2, (iii) m = 2, (iv) m = 2, (v) m = 1.82, (vi) m = 2, (vii) m = 2, (viii) m = 2; b) m \approx 2; c) The equation of the tangent line to curve at P (7, -2) is y = 2\cdot x + 12.

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}

(i) x_{Q} = 6.9:

y_{Q} =\frac{2}{6-6.9}

y_{Q} = -2.222

m = \frac{-2.222 + 2}{6.9-7}

m = 2.22

(ii) x_{Q} = 6.99

y_{Q} =\frac{2}{6-6.99}

y_{Q} = -2.020

m = \frac{-2.020 + 2}{6.99-7}

m = 2

(iii) x_{Q} = 6.999

y_{Q} =\frac{2}{6-6.999}

y_{Q} = -2.002

m = \frac{-2.002 + 2}{6.999-7}

m = 2

(iv) x_{Q} = 6.9999

y_{Q} =\frac{2}{6-6.9999}

y_{Q} = -2.0002

m = \frac{-2.0002 + 2}{6.9999-7}

m = 2

(v) x_{Q} = 7.1

y_{Q} =\frac{2}{6-7.1}

y_{Q} = -1.818

m = \frac{-1.818 + 2}{7.1-7}

m = 1.82

(vi) x_{Q} = 7.01

y_{Q} =\frac{2}{6-7.01}

y_{Q} = -1.980

m = \frac{-1.980 + 2}{7.01-7}

m = 2

(vii) x_{Q} = 7.001

y_{Q} =\frac{2}{6-7.001}

y_{Q} = -1.998

m = \frac{-1.998 + 2}{7.001-7}

m = 2

(viii)  x_{Q} = 7.0001

y_{Q} =\frac{2}{6-7.0001}

y_{Q} = -1.9998

m = \frac{-1.9998 + 2}{7.0001-7}

m = 2

b) The slope at P (7,-2) can be estimated by using the following average:

m \approx \frac{f(6.9999)+f(7.0001)}{2}

m \approx \frac{2+2}{2}

m \approx 2

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

y = m\cdot x + b

Where:

x - Independent variable.

y - Depedent variable.

m - Slope.

b - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

-2 = 2 \cdot 7 + b

b = -2 + 14

b = 12

The equation of the tangent line to curve at P (7, -2) is y = 2\cdot x + 12.

7 0
2 years ago
HELP!!!brainlist<br> Drag a reason to each box to complete the flowchart proof.
exis [7]
The complete proof statement and reason for the required proof is as follows:

Statement                                    Reason

m<PNO = 45                               Given

MO                                              Given

<MNP and <PNO are a
linear pair of angles                     Definition of linear pairs of angles

<MNP and <PNO are
supplementary angles                 Linear Pair Postulate

m<MNP + m<PNO = 180°          Definition of supplementary angles

m<MNP + 45° = 180°                 Substitution property of equality

m<MNP = 135°                          Subtraction property of equality
3 0
3 years ago
Read 2 more answers
Find the equation of the line of best fit in slope intercept form . please help
slavikrds [6]

Answer:

y = (2/5)x + 3

Step-by-step explanation:

Note that the y-intercept is (0, 3) and that the line passes right through the point (5, 5).  First we find the slope of this line:  m = rise/run.

As we move from (0, 3) to (5, 5), we see that x increases by 5 (the run) and y increases by 2 (the rise).  Thus, the slope of this line is m = 2/5.

Now we know that m = 2/5, x = 5, y = 5 and b (the y-intercept) is 3.  Then our equation is y = mx + b, or y = (2/5)x + 3

6 0
3 years ago
Read 2 more answers
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