Answer:
Y = 1/(2X+6)
Step-by-step explanation:
First, you swap X and Y, getting
X = 1/2Y - 3
Then you have to isolate Y again
X + 3 = 1/2Y -> 2Y = 1/(X+3)
Y = 1/(2X+6)
For this case we have a function of the form 
, where
To find the real zeros we must equal zero and clear the variable "x".
We add 10 to both sides of the equation
We apply cube root to both sides of the equation:
![\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x-12%29%5E3%7D%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%5C%5Cx-12%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D)
We add 12 to both sides of the equation:
![x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12](https://tex.z-dn.net/?f=x-12%20%2B%2012%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12)
Answer:
Option D
I think the answer is 2,050
Answer:
(y2-y1)/(x2-x1)
Step-by-step explanation:
Using two coordinates, you can just plug in the corresponding (x,y) coordinates and you will get the slope, which is the rate of change over an interval
A) 0+(5×2)-12+3=1
b) 0-(3×2)-1+6+7=6
c) Rosy duh ;)
