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wolverine [178]
3 years ago
12

Please help me I will give you the brain thing and extra points. (image below) 3/4

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0
First, we have to find the difference between the x and y numbers in the table. By dividing the y by the x, the c is being multiplied by 15.

So the answer would be y=15x

Brainliest please!
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What is the decimal to this fraction
6 0
3 years ago
Find the discount if a $69.99 item is on sale for $39.99.
inn [45]
The easiest way to do it (for me) is to find 1% of the regular price. I think we can round the prices to $70,00 and $40,00 to show nice percentage.

70 / 100 = 0,7

So 1% is 0,7. Now we can divide $40,00 by 0,7 to calculate how many percent it is:

40 / 0,7 = 57 (after rounding it to the nearest whole number)

So the discount was 100 - 57 = 43 percent.

Doublecheck (optional):

70 * 57% =
= 70 * 57/100 =
= 7 * 57/10 =
= 7 * 5 7,10 =
= 7 * 5,7 =
= 39,9 (the price after the discount)

70 * 43% =
= 70 * 43/100 =
= 7 * 43/10 =
= 7 * 4 3/10 =
= 7 * 4,3 =
= 30,1 (the value of the discount)

The difference of 0,1 is because of the rounding, but it's correct.

8 0
3 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
VladimirAG [237]

Answer:

A: f(x)\leq -2

Step-by-step explanation:

After graphing the equation, the highest point is (-1,-2). Since f(x) is the 2nd number in the coordinates (x, f(x)), the range is f(x)\leq -2

3 0
3 years ago
4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
8 0
3 years ago
1. My little sister, Savannah, Is three years old. She has a piggy bank that she wants to All. She
andrezito [222]

Answer:

5+ (3xn)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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