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Paha777 [63]
3 years ago
11

Which has the greater energy, light of wavelength 519 nm or light with a frequency of 5.42 x 10^8 sec^-1?

Mathematics
1 answer:
slega [8]3 years ago
8 0

Try this solution:

the rule: if f1>f2, then E1>E2, where f1;f2 - frequency, E1;E2 - energy of light.

The formula is L=c/f, where L - the wavelength, c - 3*10⁸ m/s, f - frequency.

Frequency for the wavelength 519 nm. is:

f=\frac{c}{L}=\frac{3*10^8}{519*10^{-9}}=\frac{3*10^17}{519}=578034682080924=5.78*10^{14}( \frac{1}{sec})

Answer: the energy of light of wavelength 519 nm.

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Hitman42 [59]

Hey there!

If x = -3 then replace "x" with -3

New equation: -3^-2

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3 × 3 = 3^3 = 9 (Solving for your denominator)

(-1/3)^2

= (1/9)

This your answer is: 1/9

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Answer:

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IgorLugansk [536]

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Step-by-step explanation:

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From the algebraic identity we know that

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So \frac{x^2-9}{x-3}=\frac{(x+3)(x-3)}{x-3}=x+3

(b) \frac{x^3-27}{x-3}

We know the algebraic identity

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So \frac{x^3-27}{x-3}=\frac{x^3-3^3}{x-3}=\frac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9

(c) We have given \frac{x^4-81}{x-3}

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

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