Question

a rectanguluar parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 square yards find the length and the width use formula area =length * width the -parking lot width is of yards is? the length is?

Answer 1

Answer:

Required Answer:-

• Area=300yards^2

Let

Breadth =x

length=x+5

As we know that in a rectangle

${\boxed{\sf Area=lb}}$

• Substitute the values

${:}\longrightarrow$$\sf x (x+5)=300$

${:}\longrightarrow$$\sf x^2+5x=300$

${:}\longrightarrow$$\sf x^2+5x-300=0$

${:}\longrightarrow$$\sf x^2+20x-15x-300=0$

${:}\longrightarrow$$\sf x (x+20)-15 (x+20)=0$

${:}\longrightarrow$$\sf (x+20)(x-15)=0$

${:}\longrightarrow$$\sf x+20=0\:or\:x-15=0$

${:}\longrightarrow$$\sf x=-20 (Impossible)\:or \;x=15$

• Width=15yards
• Length=15+5=20yards