equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
(1,-2) and slope of 1/3
y-(-2)=1/3(x-1)
general form is ax+by=c (or ax+by+c=0) where a,b,c are integers and a is positive
y-(-2)=1/3(x-1)
y+2=1/3(x-1)
times both sides by 3
3y+6=x-1
minus 3y both sides
6=x-3y-1
add 1 both sides
7=x-3y
x-3y=7
To get ax+by+c=0 form, subtract 7 from both sides to get
x-3y-7=0
5/8 are eaten
So if you do 8/8 - 5/8 you get 3/8
Okay so for consecutive
Your first integer can be represented by the variable x.
The second number will be x+1, since it is consecutive. (For example 1+1=2, where 1 and 2 are consecutive)
So, your equation will be
x+(x+1)=-35
Combine like terms
2x+1=-35
-1 -1
—————
2x=-36
Begin isolating the variable by moving the 1 to the right
Divide each side by 2 to completely isolate x
2x=-36
—— —-
2 2
x=-18
So, one of the numbers is -18. For the other integer, insert -18.
x+1=-18+1
-17
So one integer is -17, and the other is -18. You can check by adding these integers, which gives you -35.
Hope this helps!!