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n200080 [17]
3 years ago
14

Answer please.. need asap. algebra

Mathematics
1 answer:
marta [7]3 years ago
7 0
Can be two variations

(xy)^3

3x^2y^3

Both are correct it’s just a different way of writing it
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PLZ HELP on THIS QUESTION
Greeley [361]
Its a rectangle cut the corners
8 0
3 years ago
Write the standard equation for the circle.
Kay [80]
The equation of the circle with center (h, k) and radius r is
.. (x -h)^2 +(y -k)^2 = r^2

1. selection D matches the specification of the circle

2. selection A matches the given equation

3. None of the offered selections matches
.. (x -3)^2 +(y -5)^2 = 74

4. selection A matches the requirements

3 0
3 years ago
Ter 1: Solving Simple Equation Solve x +5 = 8.​
Andru [333]

Answer:

3

Step-by-step explanation:

Step 1:

x + 5 = 8

Step 2:

x = 8 - 5

Answer:

x = 3

Hope This Helps :)

3 0
3 years ago
Read 2 more answers
Write an equation for the line (4,7) and ( 1,1)2. Write an equation for the graph
Nastasia [14]

ANSWER:

y=2x-1

STEP-BY-STEP EXPLANATION:

We have that the equation in its slope-intercept form is the following:

\begin{gathered} y=mx+b \\ m\text{ is the slope and b is the y-intercept } \end{gathered}

The slope can be calculated as follows:

m=\frac{y_2-y_1}{x_2-x_1}

We use the points (4,7) and (1,1) to calculate the slope:

m=\frac{1-7}{1-4}=\frac{-6}{-3}=2

Now, we calculate the value of b, using the point (1,1) and the slope, like this:

\begin{gathered} 1=1\cdot2+b \\ b=-2+1 \\ b=-1 \end{gathered}

Therefore, the equation would be:

y=2x-1

5 0
1 year ago
If m∠SRQ = 6x + 2 and m∠QRP = 2x + 10, find the value of x . *
Neko [114]

Answer:

for m∠SRQ x =  3

for m∠QRP x = 5

Step-by-step explanation:

1. 6x +2. 6 is being multiplied by a number so to find that number we do teh opposite

6x/2 = 3

drop the x then u have x = 3

2. 2x+10. 2 is being muliplied by a number so to find that number we do teh opposite

10/2x = 5

drop the x then u have x = 5

7 0
3 years ago
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