Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
There would be 100,000 if there are no restrictions on the digits and 90,000 if they cannot use 0 as the first digit.
If there are no restrictions, there are 10 possibilities for each digit:
10(10)(10)(10)(10) = 100,000
If the first digit cannot be 0, there are 9 possibilities for it and 10 possibilities for each of the other 4:
9(10)(10)(10)(10) = 90,000
Answer:
a⁴b⁴ - c⁴
Step-by-step explanation:
The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.
Answer:
76
Step-by-step explanation
The angle across from 104 would be the same Leaving 152 left of 360 and 152 divided by 2 is 76
