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rosijanka [135]
3 years ago
14

Are 1/2(6x-2) and 3-x equivelant?

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

6x-2/2=3x-1

because 6/2=3 and -2/2=-1

Therefore, 6x-2/2=3-x

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A rectangle has long sides measuring 4 cm and short sides measuring 3 cm. What is the area of this rectangle?
bearhunter [10]
Area of this rectangle
4×3=12cm^2

formula
long side×short side=area of this rectangle
8 0
3 years ago
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Use the given graph to determine the limit, if it exists. A coordinate graph is shown with an upward sloped line crossing the y
AURORKA [14]

Answer:

does not exist

Step-by-step explanation:

3 0
3 years ago
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A system of equations is shown below: n = 3m + 7 n − 2m = 1 What is the solution, in the form (m, n), to the system of equations
LiRa [457]
N=3 m+7
n-2 m=1     | -2 m      => n=1+2m

n=3 <span>m+7
</span><span>n=1+2 m
</span>
n=n

3m+7=1+2m       |-7 and -2m
m = -6

n=1+2m 
n=1+2*(-6)
n=-11

(-6,-11)
8 0
4 years ago
Read 2 more answers
Duncan's Bakery sold one customer 1 dozen chocolate cookies and 10 dozen oatmeal cookies
MAXImum [283]

Answer:

Dozen Oatmeal = $4 and Dozen Chocolate = $9

Step-by-step explanation:

Dozen Oatmeal:

10 dozen oatmeal and 1 dozen chocolate =$49

9 dozen oatmeal and 1 dozen chocolate = $45

The second customer bought 1 less dozen and paid $4 fewer dollars, therefore 1 dozen oatmeal must equal $4

Dozen Chocolate: let C = 1 dozen chocolate

10 dozen oatmeal + 1 dozen chocolate = $49

(10 x $4) + C = $49

$40 + C = $49

-40             -40

C = $9

1 dozen chocolate cookies = $9

3 0
3 years ago
Please help thank u
puteri [66]

Answer:

2 {x}^{2}  + 13x + 15 \\ 2 {x}^{2}  + 10x + 3x + 15 \\ 2x(x + 5) + 3(x + 5) \\ (2x + 3)(x + 5)

5 {x}^{2} +  21x + 4 \\ 5 {x}^{2}  + 20x + x + 4 \\ 5x(x + 4) + 1(x + 4) \\ (5x + 1)(x + 4) \\

7 {x}^{2}  - 59x + 24 \\  7 {x}^{2}  - 56x - 3x + 24 \\ 7x(x - 8) - 3(x - 8) \\ (7x - 3)(x - 8)

2 {x}^{2}  + 11x - 13 \\ 2 {x}^{2}   - 2x + 13x - 13 \\ 2x(x - 1) + 13(x - 1) \\ (2x + 13)(x - 1)

8 {x}^{2}  + 29x - 12 \\ 8 {x}^{2}  + 32x - 3x - 12 \\ 8x(x + 4) - 3(x + 4) \\ (8x - 3)(x + 4) \\  \\

12 {x}^{2}  - 7x - 12 \\ 12 {x}^{2}   + 9x - 16x- 12 \\3x(4x + 3) - 4(4x + 3) \\ (3x - 4)(4x + 3)

- 12 {x}^{2}  - 35x - 18 \\  - 12 {x}^{2}  - 8x - 27x- 18 \\  - 4x(3x - 2) - 9(3x - 2) \\ ( - 4x - 9)(3x - 2)

6 0
3 years ago
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