SOLUTION
![\begin{gathered} a\text{. }\frac{-1}{3}\text{ + }\frac{6}{7} \\ \\ \frac{-7+18}{21} \\ \\ \frac{11}{21} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5Ctext%7B.%20%7D%5Cfrac%7B-1%7D%7B3%7D%5Ctext%7B%20%2B%20%7D%5Cfrac%7B6%7D%7B7%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B-7%2B18%7D%7B21%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B11%7D%7B21%7D%20%5Cend%7Bgathered%7D)
b.
![\begin{gathered} \frac{15}{16}-\frac{3}{4} \\ \\ \frac{15-12}{16} \\ \\ \frac{3}{16} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B15%7D%7B16%7D-%5Cfrac%7B3%7D%7B4%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B15-12%7D%7B16%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B3%7D%7B16%7D%20%5Cend%7Bgathered%7D)
c.
![\begin{gathered} \frac{7}{6x}+\frac{-4}{3y} \\ \\ \frac{7y-8x}{6xy} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B7%7D%7B6x%7D%2B%5Cfrac%7B-4%7D%7B3y%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B7y-8x%7D%7B6xy%7D%20%5Cend%7Bgathered%7D)
So we just have to find the LCM of the denominators, then we perform the rule of addition of fraction
Answer:
i
Step-by-step explanation:
![\begin{array}{lclcr}i^{1} & = &(\sqrt{-1})^{1}&=& i\\i^{2} & = & (\sqrt{-1})^{2}& =&-1\\i^{3} & = & (\sqrt{-1})^{3}&=&-i\\i^{4} & = & (\sqrt{-1})^{4}& = &1\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blclcr%7Di%5E%7B1%7D%20%26%20%3D%20%26%28%5Csqrt%7B-1%7D%29%5E%7B1%7D%26%3D%26%20i%5C%5Ci%5E%7B2%7D%20%26%20%3D%20%26%20%28%5Csqrt%7B-1%7D%29%5E%7B2%7D%26%20%3D%26-1%5C%5Ci%5E%7B3%7D%20%26%20%3D%20%26%20%28%5Csqrt%7B-1%7D%29%5E%7B3%7D%26%3D%26-i%5C%5Ci%5E%7B4%7D%20%26%20%3D%20%26%20%28%5Csqrt%7B-1%7D%29%5E%7B4%7D%26%20%3D%20%261%5C%5C%5Cend%7Barray%7D)
Multiplying by i repeats the pattern
.
Thus, any i⁴ⁿ = 1
If n = 3, 4n = 12, so
i¹² = 1 and
i¹³ = i¹ = i
Answer:
3 Is the Radius
Step-by-step explanation:
Diameter is always 2R (R for radius), as they have given us the diameter of 6 we can conclude the answer by forming a simple equations
D=2R
6=2R
3=R
Answer:
D. 6.3 in^3
Step-by-step explanation:
V= 1/3 (3.14)(r^2)(h)
V= 1/3 (3.14) (1^2)(6)
V=6.3 in^3