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Mazyrski [523]
3 years ago
5

Solve the following (23-45)+(93÷6)×23 ​

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0
334.5 ,699/2 , 334 , 1/2
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Given f(x) = 4(x - 8), determine the value of f(10).
Komok [63]

Answer:

f(x) = 4(x - 8)

        4 (10 -8) = 8

Step-by-step explanation:

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4 years ago
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What’s the value of 1 2/3 divided by 1 7/18 In mixed number fraction form someone please help :)
JulsSmile [24]
12/3=4
4 divided by 17/18 equals to 4* 18/17=72/17= 4 4/17
Thus the answer is 4 4/17
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There are 159 students to be grouped in math teams. Each team is to have the same number of students. Can each team have 3, 4, 5
Irina-Kira [14]

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3 students for each team

Step-by-step explanation:

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3 years ago
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Bentley wants to determine the height of a tree. He is 5 and 1/2 feet tall.
Talja [164]

Answer:

10.3 ft

Step-by-step explanation:

5.5/8 = x/15

multiply by 15

x=10.3 ft

4 0
3 years ago
What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

3 0
3 years ago
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