Question

The sum of the length and width of a rectangle is more than 15 units. The length is 3 units more than the width, x. Which model and solution is correct for this situation?

Answer 1

Answer: $6, 9\ \text{units}$

Step-by-step explanation:

Given

The Sum of length and width is $15\ units$

length is 3 units more than the width

width is $x$

length is $x+3$

Their sum is 15

$\Rightarrow x+x+3=15\\\Rightarrow 2x=12\\\Rightarrow x=6\ \text{units}$

Length is $x+3=9\ \text{units}$

Width is  $x=6\ \text{units}$