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2 years ago

Two numbers that multiply to equal 20 and that also equal -12

Mathematics

1 answer:

VashaNatasha [74]2 years ago

4 0

Answer:

-10 and -2

Step-by-step explanation:

ONLY IF ITS two number that mutiply to equal 20 and their sum is -12

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The rectangle below has an area of x² – 6x – 7 square meters and a width of 3 – 7 meters.

natta225 [31]

Answer:

The expression which represent the length of the rectangle is x + 1

Step-by-step explanation:

Given as :

The Area of rectangle = x² - 6 x - 7 square meters

The width of the rectangle = w = x - 7 meters

Let The length of rectangle = L meters

Now, <u>According to question</u>

∵ Area of Rectangle = Length × width

or, x² - 6 x - 7 meters² = L meters × w meters

or, x² - 6 x - 7 = L × (x - 7)

or, x² - 7 x + x - 7 = L × (x - 7)

or, x (x - 7) + 1 (x - 7) = L × (x - 7)

or, (x - 7) (x + 1) = L × (x - 7)

∴ L = $\frac{(x - 7)\times (x + 1)}{(x - 7)}$

I,e L = x + 1

So, The length of rectangle = L = x + 1

Hence,The expression which represent the length of the rectangle is x + 1 Answer

8 0

3 years ago

If we are given the value of α. How can we find the value of β?

Cloud [144]

Answer:

β = 140 - α

we know that the "missing" angle is 40° since 40 + 140 = 180

we also know that the total sum of angles in a triangle is 180

so β = 180 - 40 - α

or β = 140 - α

Step-by-step explanation:

4 0

3 years ago

Quintin stopped and bought 16.9 gallons of gas at a rate of $3.75 per gallon. How much did Quintin pay for the gas?

zmey [24]

Answer:

63.375 or $63.38

Step-by-step explanation:

Multiply the two numbers

7 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago

PLEASE HELP!

Juliette [100K]

Answer: 135 miles

Step-by-step explanation: If you go 70 miles in ones hour, then you’ll go 140 miles in 2 hours. Then it took 6 minutes longer because of traffic, and in traffic he drove 1 mile excluding 5 because he was 5 mph slower.

6 0

3 years ago

Read 2 more answers