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vova2212 [387]
3 years ago
11

Michelle baby-sits the neighbors' children. She watches the Rogers' child for $5 per hour

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0

Answer:

What is the objective to answer the question? Is it how much they will get?

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Evaluate the function below for f(3)<br> f (x) = 3x2 - 5<br> what’s the answer
Novay_Z [31]
The answer is 13 because you would plug in 3(3) which is 9 then you multiply (9)(2) which is 18 they you subtract 18-5 which equals 13
4 0
3 years ago
How many triangles can be constructed with angles measuring 50º, 90º, and 40º?
NeX [460]

Answer: Infinite


Step-by-step explanation:

We know that in a triangle the sum of all the interior angles must be 180°.

The given angles 50º, 90º and 40º

The sum of the angles 50º+ 90º + 40º= 180°

Thus, a triangle is possible with the given measurement.,

Let there is another triangle with the given angles, then by AAA similarity criteria they are similar.

Similarly, all the triangles with the same measurements of the angles must be similar.

Therefore, there are infinite number of triangles can be possible with angles measuring 50º, 90º, and 40º.

6 0
3 years ago
Read 2 more answers
Imogene invested $8,000 in a bank account that pays 8 percent simple interest at the end of each year. Her friend invested the s
Natali5045456 [20]

The right system of equations to describe the situation would be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of Imogene and her friend respectively at the end of t years.

Now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

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5 0
3 years ago
Can two rectangles with the same side lengths be congruent
sveta [45]

Answer:

the angles in squares and rectangles it's always 90° so two squares or two rectangles with same side lengths are congruent.

8 0
3 years ago
Read 2 more answers
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
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