Answer:
x = -2
Step-by-step explanation:
Solve for x:
(2 (3 x - 4))/5 = -4
Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:
(5×2 (3 x - 4))/(2×5) = -4×5/2
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) (3 x - 4) = -4×5/2
5/2 (-4) = (5 (-4))/2:
(5×2 (3 x - 4))/(2×5) = (-4×5)/2
(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:
3 x - 4 = (-4×5)/2
(-4)/2 = (2 (-2))/2 = -2:
3 x - 4 = 5×-2
5 (-2) = -10:
3 x - 4 = -10
Add 4 to both sides:
3 x + (4 - 4) = 4 - 10
4 - 4 = 0:
3 x = 4 - 10
4 - 10 = -6:
3 x = -6
Divide both sides of 3 x = -6 by 3:
(3 x)/3 = (-6)/3
3/3 = 1:
x = (-6)/3
The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:
Answer: x = -2
Answer:
Step-by-step explanation:
<u>Expand the terms in the bracket</u>
That's
Move -2x to the other side of the inequality
<u>Move - 2 to the other side of the inequality</u>
Divide both sides by 6
We have the final answer as
Hope this helps you
The leg rule is hypotenuse/leg and the altitude rule is side 1/altitude=altitude/side 2
D = (5-1)/(13-(-3)) = 0.25
f(13) = 13d + x = 13 * 0.25 + a = 3.25 + a = 5
a = 1.75
f(x) = 1.75 + 0.25x
Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
If b² > 4ac the solutions are real. If b²-4ac is a perfect square, the solutions are real and rational; otherwise they’re real but irrational.
If b² < 4ac the solutions are complex.
