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3 years ago

12

Which range contains the value of √25-4+16?

1 answer:

muminat3 years ago

3 0

Answer:

A) Between 6.0 and 6.2

Step-by-step explanation:

$\sqrt{25-4+16} \\\sqrt{41-4}\\\sqrt{37}$

6.08

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The diameter of a circle is 20 ft. Find its area in terms of <br> π

olchik [2.2K]

Answer:

314.16 might be wrong but hope it helps!

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2 years ago

Answer this math question pls I'm in a rush

777dan777 [17]

Answer:

61/18

Step-by-step explanation:

Make the mixed fraction an improper fraction first. So instead of 1 1/3, it'll be 4/3.

Now in a rectangular prism, there's two of each congruent sides (three pairs in total).

You'll need to multiply (4/3)(3/4) by 2 because there's two of them.

This gives you (1)(2) which equals 2.

Next, take another set --> (4/3)(1/3)(2) again because there's two of them.

This gives you (4/9)(2) which equals 8/9.

Last, take the last set --> (3/4)(1/3)(2)

This gives you (1/4)(2) which equals 1/2.

Now that you have all the areas of the rectangles, add them all together.

2+8/9+1/2 which equals 61/18 inches squared.

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3 years ago

Help me please id really appreciate your help

yulyashka [42]

Answer:

See explanation below

Step-by-step explanation:

Volume = (11)(10)(7) = 770 cubic centimeters

Surface area = (2)(10)(7) + (2)(11)(7) + (2)(11)(10) = 1774 square centimeters

b) Surface area (How much wax can cover the cube)

c) Volume (How much juice will be inside the cube)

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3 years ago

Read 2 more answers

A circuit shows that the impedance of a component is −56i−56i. Is the component a resistor, a capacitor, or an inductor? Select

AlekseyPX

Answer:

c

Step-by-step explanation:

5 0

3 years ago

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

4 years ago