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3 years ago

6

Temperature fell on one night in London to 12 degrees centigrade. On same night in Moscow temperature fell to -5degrees centigra

de What was the difference in temperature?

1 answer:

galina1969 [7]3 years ago

8 0

Answer:

17(maybe)

Step-by-step explanation:

12-(-5)=17

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Estimate the quotient to the nearest whole number by using compatible numbers 7.73 divided by 1.73

Alex73 [517]

If you divide on a calculator, you get 4.468208092, so I would say the answer is 4.4, since the number after 4 is 6, which is more than 5, I round to the 4. Hope this helps!

Aye Sir!

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3 years ago

In the united state 13 out of every 20 cans are recycled. What percent of can are recycled

lyudmila [28]

Answer:

13%

Step-by-step explanation:

Just turn the amount of cans recycled into a percent

8 0

3 years ago

A bed is 2400 a discount of 25% was given on the

Brrunno [24]

Answer:

800

Step-by-step explanation:

Given: The selling price of bed is 2400.

Discount offered is 25%

Lets assume the cost of bed be "x"

Discount offered on the cost price of bed= $\frac{25}{100} \times x= 0.25x$

∴ Discount offered on the cost price of bed= 0.25x

We know the selling price of bed after discount provided.

Finding the cost price of the bed.

⇒ $x-0.25x= 2400$

⇒ $0.75x= 2400$

cross multiplying both side.

∴ $x= \frac{2400}{0.75} = 3200$

∴ Cost price of the bed is 3200.

We know selling price of the bed is 2400.

Now, finding the saving.

Saving on the price of bed= Cost price- selling price

Saving= $3200-2400= 800$

Hence, saving on the purchase of the bed is 800.

7 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Please help me out with this problem!

MA_775_DIABLO [31]

Answer:

C

Step-by-step explanation:

The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.

Given y = f(x) then f(x + a) is a horizontal translation of a units

• If a > 0 then shift to the left of a units

• If a < 0 then shift to the right of a units

Here shift to the right of 1 unit, thus

y = f(x - 1)

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

Note the y- coordinates are the negative of each other, thus

- y = f(x)

Now $\frac{y}{-1}$ = - y, hence

The equation for the red graph is

$\frac{y}{-1}$ = f(x - 1) → C

6 0

3 years ago