Answer:
The question is incomplete, so I will describe the sine regression model.
The function
y = 0.884 sin(0.245x - 1.093) + 0.400
correspond to the general equation:
y = a sin(bx - c) + d
where:
a = 0.884
b = 0.245
c = 1.093
d = 0.400
The amplitude of the function is computed as follows:
amplitude = |a| = 0.884
The period of the function is computed as follows:
period = 2π/|b| = 25.6456
The phase shift of the function is computed as follows:
phase shift = c/b = 4.4612 to the right (because there is a minus sign before c in the equation)
The vertical shift of the function is computed as follows:
vertical shift = d = 0.400
The answer is 120 miles , because it is a proportion
Answer:
D
Step-by-step explanation:
when a number is added at the end it results in a vertical transformation
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213