Please help me with this!!

What is the base of a rectangle with a height of 12.6 meters and an area of 28.98 square meters? Enter your answer in the box.

Arada [10]

Answer:

why is brainlys ask a tutor not free anymore I really needed help so I pressed the button and all it said was pay for tutor plus

4 0

2 years ago

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How do you draw a line for this

m_a_m_a [10]

I'd do a little more than 77minutes for the 6and 7for if you could have it on 77and but you could have it in your head

8 0

3 years ago

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Solve for x. Write the smaller solution first, and the larger solution second.

xeze [42]

Answer:

x= 1 or x=7

Step-by-step explanation:

2 x 2− 16 x + 14 =0

2 (x−1) (x−7)=0

x−1=0 or x−7=0

x=1 or x=7

4 0

3 years ago

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9. Michelle likes chocolate but it causes acne. She chooses to limit herself to three chocolate bars every 5 days. (So, she eats

OverLord2011 [107]

Answer:

Arithmetic

An = A[n - 1] + 3/5

An = 3/5[n]

Step-by-step explanation:

Number of days = 5

Number of chocolate = 3

Computation:

Recursive:

Number of chocolate eat per day = 3/5

So,

First term a1 = 3/5

So,

An = A[n - 1] + 3/5

Explicit:

An = 3/5 + 3/5[n-1]

An = 3/5[n]

4 0

3 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago