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lilavasa [31]
3 years ago
11

A tree farm sold a total of 380 trees.

Mathematics
2 answers:
valentinak56 [21]3 years ago
6 0

Answer:

45

Step-by-step explanation:

Citrus2011 [14]3 years ago
4 0
The answer is 45 but don’t touch the link
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Can someone help me with this please
Stels [109]
Your answer is 90$ hope this helps and sorry if it’s wrong
8 0
3 years ago
Determine if converges or diverges. Show steps
Brut [27]
(3^x-2)/9^x=1/3^x-2/9^x
which converges by thereom
it converges to 10/72=5/36
id show work if i could but take my word,
if u cant solve it try working out a few partial sums
6 0
3 years ago
Friends needs this anwsered help
olya-2409 [2.1K]

Answer:

  3, 8, 14, 30, 58

Step-by-step explanation:

As with all formulas, put the numbers in place of the corresponding variables, and do the arithmetic.

  a_1=3\qquad\text{given}\\\\a_2=8\qquad\text{given}\\\\a_3=2a_1+a_2=2(3)+8=14\\\\a_4=2a_2+a_3=2(8)+14=30\\\\a_5=2a_3+a_4=2(14)+30=58

The first 5 terms of the sequence are 3, 8, 14, 30, 58.

4 0
2 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
It took Aiden 6 hours to plant 8 trees. How many hours would it take for him to plant 20 trees? 24, 18, 23, 15
Pepsi [2]
<h3>Answer: 15 hours (choice D)</h3>

================================================

Work Shown:

(6 hours)/(8 trees) = (x hours)/(20 trees)

6/8 = x/20

6*20 = 8*x ... cross multiply

120 = 8x

8x = 120

x = 120/8

x = 15

It takes him 15 hours to plant 20 trees.

7 0
2 years ago
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