No. Zachary should have drawn the first two arcs with the compass centered at B.

The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter

JulsSmile [24]

Answer:

1) n=114

2) n=59

3) On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.2$ and $\alpha/2 =0.1$ . And the critical value would be given by:

$z_{\alpha/2}=-1.28, z_{1-\alpha/2}=1.28$

Part 1

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.06$ or 6% points, and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimate of $\het p$ we can use 0.5 as a good estimate, replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.06}{1.28})^2}=113.77$

And rounded up we have that n=114

Part 2

On this case we have a prior estimate for the population proportion and is $\hat p =0.85$ so replacing the values into equation (b) we got:

$n=\frac{0.85(1-0.85)}{(\frac{0.06}{1.28})^2}=58.027$

And rounded up we have that n=59

Part 3

On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

5 0

3 years ago

Find the Value of each power.

Alexxandr [17]

Answer:

1

144

8/343

0.16

4/9

0.343

4 0

2 years ago

Becky needs to put 4 cups of flour into her bread maker to make one loaf of bread. She is using a measuring cup that holds 13 cu

pav-90 [236]

Answer:

12

Step-by-step explanation:

From the above question, we ate told that:

Becky needs to put 4 cups of flour into her bread maker to make one loaf of bread.

The size of her measuring cup = 1/3 cup

The number of 1/3 cups of flour she will need to make a loaf of bread is calculated as:

4 cups of flour ÷ 1/3 cup of flour

= 4 cups of flour × 3/1 cup of flour

= 12

4 0

2 years ago

A jewelry store is having a 50% off sale for all necklaces. During this sale, what is the cost of a necklace that regulary costs

Ymorist [56]

50% off means half price, so half of 49.98 is 24.99
the necklace now costs 24.99 dollars

3 0

3 years ago

After losing 3 baseball cards, Peter gave half of his remaining cards to Bobby. If Peter gave Bobby 9 baseball cards, how many c

seropon [69]

If Bobby claims Peter started with 21 cards, then we'll work this into our equation.

21 - 3 (that he lost) = 18
18 / 2 (the half he gave) = 9

So this means that he did have 21 cards to begin with. Please reply to this with a list of the answers that can/could be checked!

6 0

3 years ago

Read 2 more answers