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forsale [732]
2 years ago
6

Pls help :(

Mathematics
1 answer:
user100 [1]2 years ago
4 0

Answer:

A candle holder holds a candle

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What is an equivalent expression to 5(m+1)-1
adelina 88 [10]

Answer:

is this answer

Step-by-step explanation:

5(m+1)-1

5m+5-1

5m-4

7 0
2 years ago
Which of the following is a requirement for a trinomial to be factored as a perfect square? A. The coefficient for the x^2 term
prisoha [69]
For the trinomial to be a perfect square trinomial the coefficient for the x^2 term must. E a perfect square.
Letter C
4 0
3 years ago
State the slope-intercept form of the equation for the graph with the points 3,0 and 0,-1
Dvinal [7]

Answer:

The answer is y=1/3x-1

Step-by-step explanation:

m=1/3

y-y=m(x-x1)

y-(-1)=1/3(x-0)

y+1=1/3x-0

-1 -1

y=1/3x-1

6 0
3 years ago
Please Answer I don't understanddd
Tamiku [17]
C = 2 pi r given r = 4
so
C = 2 pi (4)
C = 8 pi

answer
C. C = 8pi 
3 0
3 years ago
F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
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