Pls help :(

Anyone know what 4x + 2y - 6z -x -3y + 2z ?

____ [38]

4x+2y-6z-x-3y+2z= 3x-y-4z

For more help use math/way/./com

6 0

3 years ago

Read 2 more answers

What is the least common multiple of 2, 3, and 20?

tia_tia [17]

Answer:

60

Step-by-step explanation:

The least common multiple of 2 and 20 is 20.

The only factor that is shared with 20 and 3 is 1. Therefore, the least common multiple will have to be 20*3, which is 60.

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3 0

2 years ago

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A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

You purchase a car in 2010 for $25,000. The value of the car decreases by 14% annually. What would the value of the car be in 20

Fed [463]

Answer: -$6,500

Step-by-step explanation:

Here we could , use the arithmetic progression where

T(2020 - 2010) = a + ( n - 1 )d

T10 = a + ( 10 - 1 )d --------------- 1

a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.

Note since it decreases the common difference d = -$3,500.

Now substitute for the values in the equation above.

T10 = 25,000 + 9 x -3,500

= $25,000 - $31,500

= -$6,500 (deficit )

4 0

2 years ago

A number chosen at random from 1 to 10 find the probability of selecting a 5 or greater

ZanzabumX [31]

The probablility is 1/2 or 0.50 % chance.

8 0

3 years ago