How can this quadrilateral be classified?
2 answers:
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Answer: The speed of rowing is 3.56 miles per hour and speed of current is 1.06 miles per hour.
Step-by-step explanation:
Since we have given that
Let the speed of boat in still water be 'x'.
Let the speed of current be 'y'.
Distance = 1 mile
For Upstream, speed would be
For downstream, speed would be
By graphing method we get that
x = 3.558 miles/hr
and y = 1.058 miles/hr
Hence, the speed of rowing is 3.56 miles per hour and speed of current is 1.06 miles per hour.
Refer to the diagram shown below.
BE = 2x² - x
DE = x² + 6
The intersecting diagonals bisect one another.
Therefore BE = DE, so that
2x² - x = x² + 6
x² - x - 6 = 0
Factorize.
(x + 2)(x - 3) = 0
x = -2, or x = 3.
When x = -2,
BE = 2(-2)² - (-2) = 10
DE = (-2)² + 6 = 10
Therefore BD = 20
When x = 3;
BE = 2(3²) - 3 = 15
DE = 3² + 6 = 15
Therefore BD = 30
Answer: Either 20 or 30.
BE = 2x² - x
DE = x² + 6
The intersecting diagonals bisect one another.
Therefore BE = DE, so that
2x² - x = x² + 6
x² - x - 6 = 0
Factorize.
(x + 2)(x - 3) = 0
x = -2, or x = 3.
When x = -2,
BE = 2(-2)² - (-2) = 10
DE = (-2)² + 6 = 10
Therefore BD = 20
When x = 3;
BE = 2(3²) - 3 = 15
DE = 3² + 6 = 15
Therefore BD = 30
Answer: Either 20 or 30.