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4 years ago

Which statement is true for the equation 3x − 3x − 2 = −2?

Mathematics

2 answers:

Amanda [17]4 years ago

8 0

Answer:

D. It has infinitely many solutions.

Step-by-step explanation:

We have been given an equation $3x-3x-2=-2$ . We are asked to find the number of solutions for our given equation.

We know that an equation has infinitely many solutions, when both sides of the equation are equal.

Let us add 3x on both sides of our given equation.

$3x-3x+3x-2=-2+3x$

$3x-2=3x-2$

Since both sides of our given equation are equal, therefore, our given equation has infinitely many solutions and option D is the correct choice.

coldgirl [10]4 years ago

4 0

It would come out to 3x = 3x so it would be infinitely many solutions

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How are slope 1 and slope 2 related?

Diano4ka-milaya [45]

The answer is B. Adjacent angles. They both have a meeting point and don't overlap.
The answer isn't A. because both angles don't add up to 90°.
The answer isn't C. because both angles aren't 90°.
The answer isn't D. because both angles don't add up to 180°.

Hope this helps! :)

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4 years ago

write the equation of a line in any form that is parallel 2y = 4x + 8 through the point of (1,3) plz and thank you

V125BC [204]

Answer:

y = 2x+1

Step-by-step explanation:

$2y =4x+8\\\\ Write \:in \: y =mx+b \:form\\\\\frac{2y}{2} = \frac{4x}{2} +\frac{8}{2} \\\\y =2x +4\\m =2\\(1,3) =(x_1,y_1)\\Substitute\:values\:into\:point-slope\:form\\\\y-y_1=m(x-x_1)\\y-3=2(x-1)\\y-3 = 2x-2\\y=2x-2+3\\y =2x+1$

4 0

3 years ago

Read 2 more answers

2 questions in the 2 pictures and then im done thank you

Tamiku [17]

Answer:

Hey there!

For the first question we use the triangle area formula: 1/2bh, or 1/2(8)(5). This gives us 20 for the area.

For the second question we get a trapezoid, since the cross section does not pass through the vertex.

Hope this helps :)

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4 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

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fredd [130]

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3 years ago

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