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Ludmilka [50]
4 years ago
11

A function f is depicted in the graph. Find any input values that produce the indicated output. 

Mathematics
1 answer:
Kruka [31]4 years ago
3 0
See that the point (-2,-1) belongs to graph, so (-2,-1) is one searched point
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25% each or .25 her plus three friends =4 /4 =1 /
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Step-by-step explanation:

5 0
3 years ago
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Find the equation of the line that passes through point A (1,7) and B (-3, -1)
amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

6 0
3 years ago
Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,
alexgriva [62]

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

\frac{sin(B)}{b} = \frac{sin(C)}{c}

\frac{sin(B)}{24} = \frac{sin(82)}{29}

sin(B)*29 = sin(82)*24

\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}

sin(B) = \frac{sin(82)*24}{29}

sin(B) = 0.8195

B = sin^{-1}(0.8195)

B = 55.0

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

\frac{a}{sin(43)43} = \frac{24}{sin(55)}

Cross multiply

a*sin(55) = 25*sin(43)

a = \frac{25*sin(43)}{sin(53)}

a = 20 (approximated)

8 0
3 years ago
How do you know when a polynomial is factored completely?
34kurt
When you cannot simplify it further. The terms have no common factor besides 1 and A plus C does not have two numbers that multiply to the total and equal C.
6 0
3 years ago
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