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3 years ago

I NEED HELP ASAP !!!!

Mathematics

1 answer:

mestny [16]3 years ago

8 0

D would me the answer I just took the assignment

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The escalator rises 25° from the ground and a vertical distance of 42 feet. How much horizontal distance does the escalator cove

zvonat [6]

Tangent (25) = opp / adj = 42 / horizontal distance
horizontal distance = 42 / tangent (25)
horizontal distance = 42 / 0.46631
horizontal distance = 90.068838326435200 
horizontal distance = 90.1 feet

5 0

3 years ago

[tex]\frac{3}{8} of 10x

pentagon [3]

Answer: x = 3/80

Step-by-step explanation:

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2 years ago

greg is designing the clock face for a homemade clock. using the center of the clock face as the origin, he places the label 12

Serjik [45]

I apologized that you have not been helped yet, But the answer is (0,-5). Again, I am so sorry that you were not helped properly :)

8 0

3 years ago

Evaluate triple integral ∫ ∫ ∫ 8xydV, where E lies under the plane z = 1+x+y and above the E region in the xy-plane bounded by t

vazorg [7]

Answer:

$\mathbf{=\dfrac{163.384}{15}}$

Step-by-step explanation:

$\int \int \limits_{E} \int \ 8 xy dV = \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} \int\limits^{1+x+y}_{0} \ 8xy dz dydx$

$= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} [ 8xyz]^{z=1+x+y}_{z=0} \ \ dy dx$

$= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy (1+x+y) dy dx$

$= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy+8x^2y+8xy^2 \ \ dy dx$

$= \int\limits^{1}_{0} \ [ 4xy^2+4x^2y^2+2.7xy^3]^{ y= \sqrt{x}}_{y-0} \ \ dx$

$= \int\limits^{1}_{0} \ 4x (\sqrt{x})^2+4x^2(\sqrt{x})^2+2.7x(\sqrt{x})^3\ \ dx$

$= \int\limits^{1}_{0} \ 4x^2+4x^3+2.7x^{5/2} \ dx$

$\mathbf{=\dfrac{163.384}{15}}$

7 0

3 years ago

When point A( 3, 1) is translated 2 units to the right and 6 units up the coordinates of point A'

9966 [12]

Answer:

A' = (5,7)

Step-by-step explanation:

So, we start with the original point A at (3,1), that means x = 3 and y = 1.

We move it 2 units to the right... so we're moving along the X-axis... and we're moving to the right.. so we're increasing the value of x. That means starting with x = 3, we go 2 more units... we then get to x = 5.

In the same way, we move 6 units up... so we move along the Y-axis. We go up, so we also increase the value of y. Starting with y = 1, we move up by 6 units... so we are now at y = 7.

A' point is then at (5,7).

3 0

2 years ago