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Lostsunrise [7]
3 years ago
10

The case of a rectangular electronic tablet has an area of A square inches. The length of the case is 12.5 in. Which equation re

presents h, the height of the case in inches?
Need an answer quick! :)
Mathematics
2 answers:
Alik [6]3 years ago
8 0
...........???.???.?.
MissTica3 years ago
3 0

Answer:

A=12.5xh

Step-by-step explanation:

I think this should be right

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garik1379 [7]

Answer:

you still need help

Step-by-step explanation:

8 0
3 years ago
Which list shows the in greatest to least?<br><br>(NEED ASAP)
NeX [460]

The answer is B.

\frac{14}{5} = \frac{28}{10}

\frac{5}{2} = \frac{25}{10}

1\frac{3}{10} = \frac{13}{10}

\frac{3}{5} = \frac{6}{10}

If you find a common denominator, the process becomes much easier. I hope this was helpful.

8 0
3 years ago
What is the value of x?​
ANTONII [103]

Answer:

its x=2

Step-by-step explanation:

5 0
3 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
3 years ago
Which expression represents the following statement: x is no less than 0. x&gt;0 x≤0 x≥0 x&lt;0
ki77a [65]

Answer: x ≥ 0

Step-by-step explanation:

First, let's define the symbols used:

a < x              (this means that a is strictly smaller than x)

a > x              (this means that a is strictly larger than x)

a ≤ x              (this means that a is smaller than or equal to x)

a ≥ x              (this means that a is larger than or equal to x)

Now we have the statement "x is no less than 0"

Then x can be equal to zero, or larger than zero, but never smaller than zero.

Looking at the symbols above, we know that we need to use:

x ≥ 0

(this is equivalent to the statement)

7 0
3 years ago
Read 2 more answers
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