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3 years ago

Can anyone help me please? I have no idea what to do! :'(

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Answer:

7) 10^(3/2)

8) 2^(1/6)

9) 2^(5/4)

10) 5^(5/4)

Step-by-step explanation:

7) (√10)^3 = 10^(3/2)

8) 6 root 2 = 2^(1/6)

9) (4 root 2)^5 = 2^(5/4)

10) (4 root 5)^5 = 5^(5/4)

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Suze wants to make 5 pies for a party. She needs 1 1/2 cup of confectioners sugar for each pie. She has two bags of confectioner

Lunna [17]

Answer:

1 7/8 cups leftover

Step-by-step explanation:

The total amt. of sugar Suze needs is 5(1 1/2 cups) = 15/2 cups, or 7.5 cups.

Combining the 3 1/4 and 6 1/8 cups of sugar remaining in the bag results in 3 2/8 + 6 1/8 cups, or 9 3/8 cups total. She needs only 7.5 cups of this sugar.

Thus, she has leftover the following amount: 9 3/8 - 7 4/8 cups, which

simplifies to 1 7/8 cups

5 0

3 years ago

Read 2 more answers

A sociologist randomly selects single adults for different groups of three, and the random variable x is the number in the group

Bas_tet [7]

Answer:

This data is not a probability distribution

The reason sum of the probabilities is not equal

∑ P(X=x) ≠ 1

Step-by-step explanation:

Explanation:-

Given data

x 0 1 2 3

p(x) 0.091 0.334 0.408 0.166

Discrete distribution :-

Probability distribution of a random variable is the set of its possible values together with their respective probabilities. Suppose X is a discrete random variable with possible outcomes (values) x₁ , x₂ , x₃ ,......... The probability of each possible outcome

$p_{i} = P(x=x_{i}) = p(x_{i}) for I= 1,2,3......$

If the numbers $p(x_{i}) , I =1 ,2,3,.....$ satisfy the two conditions

i) $p(x_{i}) \geq 0 for all values of i$

ii) ∑P(X=x) =1

Given data condition(i) satisfied $p(x_{i}) \geq 0 for all values of i$

but the condition (ii) is not satisfied

0.091+0.334+ 0.408+ 0.166 = 0.999

sum off all probabilities is not equal to one

Conclusion:-

The given data is not probability distribution

6 0

4 years ago

What is the equation that passes through the points (-2,-4) & (8,1) ??? Please help thanks.

Marizza181 [45]

To solve a Linear equation we need to find the slope:

-4-1 / -2-8 =1/2

now that we have the slope we can find our x and y
y-1=1/2(x-8)
y=x/2-3

5 0

3 years ago

HELP PLEASEEEE

Olin [163]

Answer:

3/8

Step-by-step explanation:

5 0

3 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago