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2 years ago

13

Please help i have been trying to figure this out for like an hour

1 answer:

KengaRu [80]2 years ago

7 0

Answer:

B

Step-by-step explanation:

Since x varies directly as y, the ratio of x to y remains the same. Let the value of x when y=4 be a. Then we have

$\dfrac {7 \frac12} {10} = \dfrac a4$

We can cross multiply to get that

$10a = 30, \text{so } \boxed{a=3}$

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Put this equation into slope intercept -2×+3y=9

siniylev [52]

y = $\frac{2}{3}$ x + 3

The equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange - 2x + 3y = 9 into this form

add 2x to both sides

3y = 2x + 9 ( divide all terms by 3 )

y = $\frac{2}{3}$ x + 3 ← in slope-intercept form

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3 years ago

Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the

Dominik [7]

G=37

Angle ACD and angle DCB are a linear pair. Meaning they are supplementary.

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180-90=90

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2 years ago

Jesus is the son, the spirit, and the Living of God! ...

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Step-by-step explanation:

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2 years ago

4 -12 36 -108 324 what's the rule

balandron [24]

Hello,
$u_{1}=4\\
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2 years ago

When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It

Delvig [45]

Answer:

$c=1$ and $c=-12$

Step-by-step explanation:

The correct equation is:

$c^2+11c=12$

To solve by completing the square method.

Solution:

We have:

$c^2+11c=12$

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

$c^2+2.\frac{11}{2}c=12$

$c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2=12$ [As $c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2$ ]

Adding both sides by $(\frac{11}{2})^2$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2$

$(c+\frac{11}{2})^2=12+\frac{121}{4}$

Taking LCD to add fraction.

$(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}$

$(c+\frac{11}{2})^2=\frac{169}{4}$

Taking square root both sides.

$\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}$

$c+\frac{11}{2}=\pm\frac{13}{2}$

Subtracting both sides by $\frac{11}{2}$ :

$c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}$

$c=\pm\frac{13}{2}-\frac{11}{2}$

So, we have:

$c=\frac{13}{2}-\frac{11}{2}$ and $c=-\frac{13}{2}-\frac{11}{2}$

$c=\frac{2}{2}$ and $c=\frac{-24}{2}$

$c=1$ and $c=-12$ (Answer)

6 0

3 years ago