Please help i have been trying to figure this out for like an hour
1 answer:
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Answer:
Therefore,
ΔABD ~ ΔACB by Angle-Angle Similarity Postulate
AB is 8 unit.
Step-by-step explanation:
Given:
∠ABD ≅ ∠BCD
AD = 4
DC = 12 Therefore AC =AD + DC = 4 +12 =16
AC =16
To Find:
Similar Triangles
AB =?
Solution:
In ΔABD and ΔACB
∠ABD ≅ ∠ACB ……….{Given}
∠ A ≅ ∠ A .……..{Reflexive Property}
ΔABD ~ ΔACB ….{By Angle-Angle Similarity Postulate}
If two triangles are similar then their sides are in proportion.
Substituting the values we get
Therefore,
ΔABD ~ ΔACB by Angle-Angle Similarity Postulate
AB is 8 unit.
Answer:
a)
The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.
The incenter is located at the intersection of bisectors of the interior angles of a triangle.
b)
The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.
The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.
c)
<em>See the attachment</em>
The blue lines and their intersection shows the incenter.
The red lines and their intersection shows the circumcenter.
As we see the red point- the <u>circumcenter </u>is closer to vertex B.
